1/2(2b^2-4)5b

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Solution for 1/2(2b^2-4)5b equation: 


b in (-oo:+oo)

(1/2)*b*(2*b^2-4)^5 = 0

1/2*b*(2*b^2-4)^5 = 0

( 1/2*b )

1/2*b = 0 // : 1/2

b = 0

( 2*b^2-4 )

2*b^2 = 4 // : 2

b^2 = 2

b^2 = 2 // ^ 1/2

abs(b) = 2^(1/2)

b = 2^(1/2) or b = -2^(1/2)

b in { 0, 2^(1/2), -2^(1/2), 2^(1/2), -2^(1/2), 2^(1/2), -2^(1/2), 2^(1/2), -2^(1/2), 2^(1/2), -2^(1/2) }

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